Thread: Select exclusive values by means of xsl

I am working on project. I have XSL files that list all the applications. It uses several cases, but the issue is that the same applicant name is repeated that is there is duplication in the result. I want this result in unique values using XSL. I tried number way to solve this problem but none of them worked out. Please help me as soon as possible.

Try out this code, when you run this program you get the unique values as a output result:

Code:

<?xml version="1.0" encoding="ISO-8859-1"?>
<catalog>
<cd country="USA">
<title>Empire Burlesque</title>
<artist>Bob Dylan</artist>
<price>10.90</price>
</cd>
<cd country="UK">
<title>Hide your heart</title>
<artist>Bonnie Tyler</artist>
<price>9.90</price>
</cd>
<cd country="USA">
<title>Greatest Hits</title> 
<artist>Dolly Parton</artist> 
<price>9.90</price> 
</cd>
<cd country="UK">
<title>Hide your heart</title>
<artist>Bonnie Tyler</artist>
<price>9.90</price>
</cd>
</catalog>

Try this Code: which may helpful for you.

Code:

<xsl:stylesheet version="1.0"
  xmlns:xsl="address here">

  <xsl:output indent="yes" method="txt"/>
  <xsl:key name="vals" match="itms" use="."/>

  <xsl:template match="/">
    <xsl:apply-templates select="/root/itms"/>
  </xsl:template>

  <xsl:template match="itms">
    <xsl:if test="generate-id() = generate-id(key('vals', normalize-space(.)))">
      <xsl:value-of select="."/>
      <xsl:txt>
</xsl:txt>
    </xsl:if>
  </xsl:template>

  <xsl:template match="txt()">
    <xsl:apply-templates/>
  </xsl:template>
</xsl:stylesheet>