Thread: Can initialize fields of a structure?

For example:
typedef struct
(int a = 0;
int b = 1;
x);

Does it work?

No, x is a shape, not a value.

You can initialize the instantiation:

Code:

1.	ox = x (0,1);

Now, if you want that whenever you create an x it is automatically initialized with a = 0, b = 1 ...

... then it is time to move to C + + which provides manufacturers made to it:

Code:

1.	struct x (
2.	int a;
3.	int b;
4.	x () (
5.	a = b = 0;
6.	)7.	);

Ok thank you!

No, x is a shape, not a value.

You can initialize the instantiation:

Code:

ox = x (0,1);

Now, if you want that whenever you create an x it is automatically initialized with a = 0, b = 1 ...
... then it is time to move to C + + which provides manufacturers made to it:

Code:

struct x (
int a;
int b;
x () (
a = b = 0;
)
);

Basically is there a difference between struct and class, made by COMPLÔ C + +?

It should be an encapsulation of history ...

If I have another question.
I still have my structure X:
typedef struct
(int a;
int b;
x);

And I want to know if we can compare two instances of X:
X foo;
X bar;
foo.a = 1;
toto.b = 2;
titi.a = 0;
titi.b = 5;
Is it possible to:
if (foo == titi) {...}

Default (if nothing is specified) is private in a class and public in a structure, right?

I have another question (I feel I have forgotten everything).
If I change my toto, is it better to move the pointer argument in toto or return another X:

void modify (X * foo)
(foo-> a = 54

or

X modify (foo X)
(X temp;
temp = foo;
temp = 54;
return temp;
)

Ok but now I work in C so I can not redefine it if?

There's a solution to the so-called hard:
It works very well for your example!

Code:

Ttoto a;
Ttoto b;
[...]
if (memcmp (a, b, sizeof (ttoto) == 0)
(
)

I have another question (I feel I have forgotten everything).

If I change my toto, is it better to move the pointer argument in toto or return another X:

void modify (X * foo)
(foo-> a = 54

or

X modify (foo X)
(X temp;
temp = foo;
temp = 54;
return temp;
)

Me in this case I pass a pointer to the instance of foo in parmetre in case I want to change fields. AND I return the transaction status: OK or ERROR.

Code:

Ttoto a;
int initialize (void * foo, size)
(
if (foo == NULL) return ERROR;
if (size <1) return ERROR;
memset (foo, 0, size);
return OK;
)
if (initialize (& a, sizeof (ttoto))! = OK)
(
fprintf (stderr, "There's a testicle.  n");
return or exit ...
)

Code:

if (memcmp (& foo, & titi, sizeof (X) == 0) / * identical * /;

But if there are holes in the structure because of alignments is not guaranteed.
There remains a macro:

Code:

# define Xequal (x1, x2) ((x1). a == (x2). a & & (x1). b == (x2). b)

You do not want to move to C + + where possible?

Code:

If I change my toto, is it better to move the pointer argument in toto or return another X:

If foo is large, it is faster to pass by address.
If foo has many members to change, it is faster to pass / return by value.
If the function should be used in expressions, it is better to return by value.
Me, I prefer by address (reference C + +).

No, x is a shape, not a value.

You can initialize the instantiation:

Code:

ox = x (0,1);

Now, if you want that whenever you create an x it is automatically initialized with a = 0, b = 1 ...
... then it is time to move to C + + which provides manufacturers made to it:

Code:

struct x (
int a;
int b;
x () (
a = b = 0;
)
);

For people who have more than 2 hours of C + + in their lives, they can put x (): a (0), b (1) ()
is much more elegant and avoids initializing ca 2 times the value.

edit: and by the way, a = b = 0 is not terrible either, it's downright pig.

how can we initialize a table structure in C
eg
struct text
(char id [20];
char pw [20];
);
typdef struct text;
text table [100];

text table [100] = (( "lol" "rofl"), .... , ( "Test", "test));